import textio.TextIO; /** * This program reads a positive integer from the user. * It counts how many divisors that number has, and * then it prints the result. * * (Note: This program works for any integer in the range * 1 to 2147483646, but it crashes with a division-by-zero * when run with input 2147483647, the largest value of type * int. This happens because 2147483647 + 1 is -2147483648, * the smallest value of type int. So, after processing * testDivisor = 2147483647, testDivisor becomes -2147483648, * and the loop continues. Eventually, testDivisor will be * zero, and the expression N % testDivisor is trying to * divide N by zero.) */ public class CountDivisors { public static void main(String[] args) { int N; // A positive integer entered by the user. // Divisors of this number will be counted. int testDivisor; // A number between 1 and N that is a // possible divisor of N. int divisorCount; // Number of divisors of N that have been found. int numberTested; // Used to count how many possible divisors // of N have been tested. When the number // reaches 10000000, a period is output and // the value of numberTested is reset to zero. /* Get a positive integer from the user. */ while (true) { System.out.print("Enter a positive integer: "); N = TextIO.getlnInt(); if (N > 0) break; System.out.println("That number is not positive. Please try again."); } /* Count the divisors, printing a "." after every 10000000 tests. */ divisorCount = 0; numberTested = 0; for (testDivisor = 1; testDivisor <= N; testDivisor++) { if ( N % testDivisor == 0 ) divisorCount++; numberTested++; if (numberTested == 10000000) { System.out.print('.'); numberTested = 0; } } /* Display the result. */ System.out.println(); System.out.println("The number of divisors of " + N + " is " + divisorCount); } // end main() } // end class CountDivisors